Find the force in all the members of the truss shown by the method of joint
Find the force in all the members of the truss shown by the method of joint MA = 0, 60*2-RD*4=0 =120 - RD*4 =0 RD = 30 KN Fy = 0, RAV +30 -60 = 0 RAV = 30 KN fy =0 FAB sin60 = -30 FAB = -34.641 KN(C) FX = 0 FAF +FAB cos60 =0 FAF - 34.641 cos60 =0 FAF -17.32 kn (T) FBD of Joint F Fx = 0 FEF - FAF =0 FEF = 17.32 KN (T) FBD OF JOINT B FY = 0 -FBESIN60-FABSIN60-FFB =0 -FBESIN60-(-34.641SIN60)-0=0 -FBE SIN60=-34.641SIN60 FBE = 34.641KN(T) FX = 0 FBC + FBE COS60 - FAB COS60=0 FBC + 34.641 COS 60+34.641 COS60=0 FBC+34.641=0 FBC = -34.641 KN(C) DUE TO SYMMETRY OF STRUCTURE FCD = FAB FGD=FAF FGE=FEF FCG=FFB FCE=FBE