A simply supported beam of span 5 m carries two point loads of 5 kn and 7kn as shown in fig . Draw SFD and BMD showing the important values.
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A simply supported beam of span 5 m carries two point loads of 5 kn and 7kn as shown in fig . Draw SFD and BMD showing the important values. MA = 0 5*1.5+7*3.5-RB=0 RB = 0.4 KN FY =0 RA+RB-5-7 = 0 RA+6.4-12 =0 RA = 5.6 KN SF BETWEEN A AND C = 5.6 KN OR, 5+7-6.4 = 5.6 KN 2) SF BTWN C AND D = 5.6 -5 = .6 KN OR 7-6.4 = .6 KN 3) SF BTWN D AND B 5.6-5-7=-6.4KN OR -6.4 KN BM CALCULATION BM AT PNT A = 0 OR, -5*1.5-7*3.5+6.4*5 = 0 2) BM AT PNT B = 0 OR 5.6*5-5*3.5-7*1.5=0 3) BM AT POINT C = 5.6 *1.5=8.4 KN/M OR, -7*2+6.4*3.5 = 8.4 KN/M BM AT D = 5.6 *3.5-5*2 =9.6KN/M OR 6.4*1.5 = 9.6 KN/M